Recent content by Jabbar

Thanks you very much! and just for my calculation mistake. Is it just that it is better to have the point of interest along one axis to do a problem. Because won't changing the axis affect my results? I can't possible change my axis mid problem no? Thanks

Oh alright, so the Electric field at that point in a) will be smaller than in b) since for dqs' on the rod... the first case will have dqs' with a greater distance r. right?

It's going to stay the same no? As the distance the two points have to dq are the same.

This is clearer image to compared to what I attached previously @gneill

This is my theta. For the second part, yeah I see that if I do that I can integrate quite easily from either -L/2 to L/2 or "x = 0 to x = L/2. Just multiply the result by two". Thanks for the insight. I just don't know why what I'm doing is wrong. Moreover, why can't I say that its electric...

Homework Statement https://gyazo.com/d502fb408d6224ffa70700cf047bad20 (link to problem: #4). [moderator edit: Image inserted for clarity] A total charge Q is distributed uniformly over rod length L. The rod is aligned on the x-axis, with one end at the origin and the other at point x=L. a)...

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