-h^2/2m (ψ'') + V(u)=Eu
I. x<0
ψ''+(2m/h)E=0
K^2=2mE/h
ψ=Ae^ikx +Be^-ikx
II. x>0
ψ''+(2m/h)(Gδ(x)-E)=0
K^2=(2m/h)(Gδ(x)-E)
ψ=Ce^kx +Be^-kx => ψ=Be^-kx
This what i got, did i make a mistake somewhere?
Homework Statement
Infinite Potential Barrier
particle moving in one dimension is incident upon a potential barrier given by V (x) = Gδ(x) where δ(x) is the Dirac delta function and G is a constant with units of energy times distance. (The delta function must have units of inverse distance...