Recent content by jahaition

-h^2/2m (ψ'') + V(u)=Eu I. x<0 ψ''+(2m/h)E=0 K^2=2mE/h ψ=Ae^ikx +Be^-ikx II. x>0 ψ''+(2m/h)(Gδ(x)-E)=0 K^2=(2m/h)(Gδ(x)-E) ψ=Ce^kx +Be^-kx => ψ=Be^-kx This what i got, did i make a mistake somewhere?

Homework Statement Infinite Potential Barrier particle moving in one dimension is incident upon a potential barrier given by V (x) = Gδ(x) where δ(x) is the Dirac delta function and G is a constant with units of energy times distance. (The delta function must have units of inverse distance...