Recent content by jahrens

Yes!

I am really struggling with this one, if anyone can help. (ln(y))3*(dy/dx)=(x^3)y with initial conditions y=e^2 x=1 I get c=4/(e^4) - 1/4 then I get stuck at (3ln^2y - ln^3y)/(y^2)=(x^4)/4 + C Any ideas? I'm really not good at these so there are probably mistakes, because at this point I have...

That's it! Thank you so much!

4 du/dt = u^2 with initial condition u(0)=6 I have worked this multiple times, and all I get is u = (-8/(t-27))^(1/3) and it is NOT right! If anyone can help it would be very appreciated.