Recent content by jake walsh

aah so if Fnet is Fresist + Fdriving then Fdriving is mass * acceleration - (-Fresist) since Fresist is in the opposite direction

The resistant force 1160 so it would be 941 * 1.25 and then that subtract that resistant force to get the actual driving force?

I think i am defining it as the amount of force required to make the car accelerate at the value 1.25m/s^2. But is that tractive force then?

Yes it was part c and D that got me really confused any advice on how to answer that? I just guessed and plugged in the mass 941 and the acceleration 1.25 into f=ma to get that number.

ok i will send a picture

I have been struggling to understand how to do this question so some guidance would be great. A racing car of mass 941kg accelerates from 28km/h to 102km/h over a distance of 297m. Frictional forces and wind resistance can be assumed to be 1160N. Determine the following: a) The average...