Recent content by JakeyTheIdiot

wait so does that mean a^2 is the minor axis squared so itd be 36? I`m not sure but I think so

Ohhh I see a^2 = 6 so the vertices are (0,-6) and (0,6)

but the thing is the vertices are already given (0,-3) and (0,3) that's why I am so confused , I think it might be the vertical kind of ellips with an equation like x^2/b^2 +y^2/a^2=1 but I have no clue what to sub in.

(h,k) = (0,0) so the center is (0,0).

Yes, I am certain :p I think the minor axis is the vertical length of the circle - - - Updated - - - Yes, I am positive! :P

Write the equation for an ellipse with vertices (0,-3) and (0,3), minor axis of length 10. I know that the standard form of an ellipse is (x-h)^2/a^2 + (y-k)^2/b^2=1 Please help me ! Please! Thank you so much for your time, I appreciate it.