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    De Broglie Wavelength of an electron

    1. The velocity of the electron in the ground state of the hydrogen atom is 2.6 x 10^8 m/s. What is the wavelength of this electron in meters?2. De Broglie's equation: lamda = h/p p=mvThe Attempt at a Solution ... (6.626 x 10^-34) / (2.6 x 10^8 x 9.11 x 10^-31) = 2.798 x 10^-12 meters This...
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