I ended up just solving the two equations:
$\dot{r}=r(4-r^2)$ and $\dot{\theta}=-1$
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I found three non-equilibrium solutions:
$r=2$ and $\theta=-1$
When $r<2$, $\dot{r}>0$, so $r$ increases and solutions move out toward the $r=2$ circle.
When $r>2$...