Hey, I was wondering if there is another way of expressing the derivative 2x(the derivative of the function x^2). I was wondering because there doesn't seem to be a y part to this. Like in y/x, a change in x makes a change in y. So how would I express this with y as well?
What is zenos paradox? and you know how for the average velocity you have y/x? Well the derivative for x squared is 2x so how would I put that in the y/x form? where does the y come into the 2x. They both change with each other so how would you represent that with 2x but more in depth?
Im looking for instantaneous velocity which Is what you put on the post. I understand the math behind finding instantaneous velocities but what doesn't make sense is with an instantaneous velocity it is the velocity at a given instant. with average velocity to find the velocity you take the...
Hey, I was wondering if you guys could give me some input in how you view velocity and what it means to you guys. I already have a rough definition in my head but I also think it would be quite helpful if I had some different input on the subject. Also, applications in real life would help as...
Ohhhhhhhhhhhhhhhh, that makes perfect sense. Since they built up distance the same just at different starting positions they will still obtain the same distance no matter what the graph distance says because their derivative is the same. Thank you all for helping me and it really does make a lot...
Ok, so this one is to Fredrik. I looked at the graph and the starting position like you said was 0,1 and for the other function 0,0. So there distances are building up the same just different positions? I looked on the graphs of these two functions and also noticed it is the same exact graph...
Ok, I understand the constant rule and how this applies but if one function is building up distance faster than another wouldn't that imply a slightly faster rate of change?
Hey guys, I had a question about two functions and many more if you look at it right, that have the same derivative. I took the derivative of x^2 and found its derivative is of course 2x. So I decided to take the derivative and x^2+1 and found the same derivative applies? How can This be...
The rule is that through any two points only one line can exist. With the quadratics the three points give you the vertex and the zeros. This is exactly what he said so is this true and if so must these points always be the vertex and the zeros?
And also, I don't think you understand where I am coming from. If you are given any amount of points, it doesn't matter how many and you don't have a graph of the function, just the points, how would you be able to determine the function and along with that the degree(im aware once you know the...
Ok, this to an extent helps me but one my friends was talking to me and he said something to the effect that you need certain points that are the characteristic on that function. Do these constants have anything to do with these characteristics of these functions?
I have asked a similar question but it wasn't answered fully so here it goes. Why is it that you only need two points to find a linear equation, three for a quadratic and so on. What determines this and is this determined because of the characteristics of these different degree polynomials?
Also what I meant by post 7 is that if you take the differences of the distances then take that difference I think it gives you an acceleration which you can add and find the velocity at that second. I think this is the same thing as the equation of the derivative where you plug in the time and...
It is very interesting that you brought in inequalities which I happen to understand quite well. I like the fact by using the inequality it LIMITS you to what you can find, haha limits are quite fun as well. This has made a lot more sense now. This really does help me connect the graphical...