Recent content by Jayker

Fnsin(theta)=mv^2 where Fn=mg/cos15 =(1450kgx9.8N/kg)/cos15 m=1450kg v=225km/h=62.5m/s theta=15 degrees

But we also know Fn Fn=(mg)/cos15 which only leaves r out of the equation to be solved for.

okay, any ideas?

Physics SPH4U-A Lesson 4 Question #15 A race-car driver is driving her car at a record-breaking speed of 225km/h. The first turn on the course is banked at 15 degrees, and the car's mass is 1450kg. a) Calculate the radius of the curvature for this turn. b) Calculate the centripetal...