Recent content by Jazzybelle4

second law is F=ma 48=m(.70) I am so lost... my teacher doesn't explain anything

any force about 48.0? there will always be friction. the coefficient needs to be smaller at .98

I found the coefficient it is .98 now i do not know what to do at all for the second part of the question (b)

so then the equation set up would look like: Ffr max= us(mg) 48N=us(mg)

Homework Statement A force of 48.0 N is required to start a 5.0 kg box moving across a horizontal concrete floor. (a) what is the coefficient of static friction between the box and the floor? (b) if the 48.0N force continues the box accelerates at 0.70m/sec2. what is the coefficient of...