Recent content by JB34

If someone could go through one of the two examples, how they would tackle it, that really would help, ultimately I only need to solve a couple of problems and then I probably won't use fractional powers for years again :frown:

Looking back at it you're right, I did say I was rusty! I've only got a couple of days to try and get my head around this ... not looking good :( \frac{1}{2}x y^{{1}/{2}} = \sqrt{\frac{z}{{x y^{-1/2}}}} ok so back to the beginning... remove the squareroot by squaring both sides...

Right so taking my first one... \frac{1}{2}x y^{{1}/{2}} = \sqrt{\frac{z}{{x y^{-1/2}}}} I was thinking along the lines of... dividing both sides by y^{{1}/{2}} gives: \frac{1}{2} x = \sqrt{\frac{z}{{x y}}} multiplying both sides by 2 x gives: x^{2} = \sqrt{\frac{2 z}{y}} square root...

As in my original post I'm looking at solving for x. Thanks for the pointers so far, I am familiar with the laws of exponents but like I said I'm very rusty, I probably haven't had to solve an equation with fractions for 10 years!

Sorry, it's shorthand from an equation editor, quite similar to latex, I'm so used to reading it that I didn't think to make it clearer :redface: So there are three variables here, x, y & z in each equation but the equations do not complement each other, they are individual examples... my first...

Hello, I'm pretty rusty when it comes to rearranging more complex equations and can't seem to remember how to deal with fractions as powers, for example; [1/2] x y^[1/2] = sqrt[[z] over [x y^-1/2]] and [2/3] x y^[-1/3] = sqrt[[z] over [x y^2/3]] I'm trying to solve a similar, but more...