Recent content by jennyyyyyy

(x+2)^2 = (√ 2x+67)^2 x^2 + 4x +4 = 2x+67 X^2 + 4x + 4 – 67 = 2x+67 –67 X^2+ 4x – 63 = 2x X^2 + 4x – 63 – 2x = 2x – 2x X^2 +2x – 63 = 0 X^2 + 9x – 7x – 63 = 0 X(x+9)-7(x+9)=0 (x+9) = 0 X-7= 0 X=-9 X=7 i solved it. i don't know if this correct though

wait wait, i get it. sorry, i got confused a bit xD (x+2)^2 = (√ 2x+67)^2 x^2 + 4x +4 = 2x+67 is it correct so far?

thank you so much! we just need to do the same step as a right?

i have been stuck this problem for a few days now. could somebody help me please?