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Solv Indefinite Integral: x^3/sqrt[1 + x^2] dx
I'm having a problem with the following integral: x^3/sqrt[1 + x^2] dx Can this be done with substitution or integration by parts? Throw me some hints at this one please! Sorry I forgot to include my attempt. I tried solving this by substitution, letting u=1-x^2. Then letting (-1/2)du =...- JimmyCat
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- Indefinite Indefinite integral Integral
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- Forum: Calculus and Beyond Homework Help