Recent content by jo3jo3520

Either I am just really dumb or not understanding but i give up. thank you for your help

help anyone?

am i supposed to do 30/15? and where in the equation do i plug this number in?

ok so .5*30 = 15 but I am confused on what to do with that? you said "Then the total change in velocity occurred over that smaller distance - not including reaction time." ?

The minimum stopping distance for a car traveling at a speed of 30 m/s is 60 m, including the distance traveled during the driver's reaction time of 0.50 s. (a) What is the minimum stopping distance for the same car traveling at a speed of 50 m/s? Vf^2 = Vi^2 +2ax So i would be...

hey thanks i found my answer...appreciate the help

A hotel elevator ascends 200 meters with a maximum speed of v= 5.0 m/s. It has a constant (net) acceleration of a +/- 1.0m/s^2. This means that the bottom floor is at 0.0meters and the top floor is at 200 meters. At rest, the v=0. when going up, it fights against gravitational acceleration of...

appreciate the input! thanks!

Ok so I have this physics problem but for some reason I feel like its a typo or I am missing some informtion, here is the problem A bicycle os moving east beginning at a position of X1=2.0m at T1=0.0s. At the time T2=2.0s find the bicycle's A) position, X2 B) velocity, V2 C) acceleration...

Im just throwing small numbers here so i can get help on the general idea...Im driving a car in uniform motion along a straight line. I go from a position x1=13m at time t1=0 secs to x2=3-m at time t2 = 30 seconds? can anyone help me with the general equation to find the position at different times?

can you tell me if i did this right...so i have this problem I am doing where i have to travel 32miles in than 45mins. what's the slowest i can drive in order to be at 32miles in 45 mins... so i divided my 45minutes by 60minutes to determine the hour value...which is .75...and then simply...

lol i just did extra work to find the length of the hypotenuse...which i didnt need i just did it lol...i greatly appreciate all your help now i understand what I am doing lol

ok so this is what i have come up with...i would take the tan (30 degrees) X 52m = My opposite side of 30m. and 52^2 + 30^2=3604^2 and the SR = 60 ...so the height of the tree is 30m?

ohhhh ok so A- should be 60 and the bottom right angle is the 30

ok so i have all the angles and 1 side (adjacent side) 52m. correct?