Recent content by jog511

  1. J

    Limit gives indeterminate form

    Homework Statement limx->∞ e^5x/ln(2x) Homework Equations The Attempt at a Solution
  2. J

    Trig Limit Homework Help: Solving (2sinxcosx)/ (2x^2 + x) at x=0

    very helpful
  3. J

    Trig Limit Homework Help: Solving (2sinxcosx)/ (2x^2 + x) at x=0

    I get lim = 2
  4. J

    Trig Limit Homework Help: Solving (2sinxcosx)/ (2x^2 + x) at x=0

    can it be written as sin2x/2x * 1/(x + 1/2)
  5. J

    Trig Limit Homework Help: Solving (2sinxcosx)/ (2x^2 + x) at x=0

    sin2x/2x will be 1 I mean
  6. J

    Trig Limit Homework Help: Solving (2sinxcosx)/ (2x^2 + x) at x=0

    the limit of sin2x/2x will be 2. am I on the right track?
  7. J

    Trig Limit Homework Help: Solving (2sinxcosx)/ (2x^2 + x) at x=0

    Homework Statement lim x->0 (2sinxcosx)/ (2x^2 + x ) Homework Equations 2sinxcosx = sin(2x) The Attempt at a Solution denom. factors to x(2x +1) how to proceed?
  8. J

    Trig Function Limit: Solving lim x->0 sin4x/2x

    thanks for your patience
  9. J

    Trig Function Limit: Solving lim x->0 sin4x/2x

    the limit is 2.
  10. J

    Trig Function Limit: Solving lim x->0 sin4x/2x

    It has to be 2
  11. J

    Trig Function Limit: Solving lim x->0 sin4x/2x

    c in the original equation was 1
  12. J

    Trig Function Limit: Solving lim x->0 sin4x/2x

    I don't understand this concept. Even Calculus by Larson does not explain it well.
  13. J

    Trig Function Limit: Solving lim x->0 sin4x/2x

    I believe I get sin4x/4x
  14. J

    Trig Function Limit: Solving lim x->0 sin4x/2x

    C = 4, y(x) = 4x
  15. J

    Trig Function Limit: Solving lim x->0 sin4x/2x

    I'll have to get back to the forum on this