dam this is a hard experiment. Yes i am doing a rod experiment.
2) I'm guessing we going to get different length of rods provided. So i assume it's T^2 vs L.
ALso. For working out the gradient. I think it's L/ T^2 =X and then re arrange the fomula. G ( gravity)= (4(pi^2)2X) / 3 is it...
T= 2pie Square root of 2L/3g
I got a couple of questions.
1) why is it 2L/3g?
2) would my straight line graph be T^2 vs L? ( so gradient is T^2/l?)
3) after i get my gradient do i compare it to the gravity 9.81?
4) is the equation going to be time^2=XXL or s^2=xxm ? do i use the unit...