Recent content by Jrogers201

Sorry I meant to say ν=10ms-1 My working out so far is as follows. For acceleration in the first 12.5s I used Total mass (lift + miners) = 5000kg + (12*80kg) = 5960kg T=mg + ma ⇒ a= (mg-T)/m = (5960kg*9.8ms-2-53640N)/5960kg =...

Thanks that helps. I did get to the stage that v=10ms-2 and the distance at 12.5s is 62.5m. From these I worked out the equation for sd=5t. I will keep on plugging at it. The textbook I'm using can be a little vague at times.

Thank you

Hi jbriggs I've definitely shown effort. I've been working on this for a week. What's throwing me is the 4 unknowns tension, distance, time and acceleration. I'm sure the answer has something to do with distance and time. I worked out part ii) quite quickly which was a=(F-mg)/m = 0.8ms -2. The...

As I mentioned I am self tutoring myself on a subject I studied 20 years ago. I'm sure I can answer all the questions apart from question (iii). I think I'm supposed to use a simultaneous equation. But I need to answer question (iii) to answer the rest. Any help please?

Studied at HND in mechanical engineering at Oldham college back in the noughties. I'm now restudying physics A level as more as a refresher. Would like to push it further. I'm getting stuck in a few places and this is all self teaching so hopefully I can help you guys out and visa versa.