Recent content by jswen92

Alright I got it! thanks for all your help :)

Okay the only other equation I found that uses distance, acceleration and time is x= volt + .5at^2 and when i solve for vo it still comes out to 4.76. am i missing something?

it comes out to 16.6 seconds and apparently that's not the right answer :/

would i do v= vo + at and use vo as 4.76 and v as 33m/s and use the a that I'm given and solve for t?

Would it be going 4.76 m/s? v=at?

A locomotive is accelerating at 1.7 m/s2. It passes through a 20.0-m-wide crossing in a time of 2.8 s. After the locomotive leaves the crossing, how much time is required until its speed reaches 33 m/s? I really don't know how to approach this equation, I feel like it will involve more than...