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Undergrad Show ##sup\{a \in \mathbb{Q}: a^2 \leq 3\} = \sqrt{3}##
I would wish to receive verification for my proof that ##sup\{a \in \mathbb{Q}: a^2 \leq 3\} = \sqrt{3}##. • It is easy to verify that ##A = \{a \in \mathbb{Q}: a^2 \leq 3\} \neq \varnothing##. For instance, ##1 \in \mathbb{Q}, 1^2 \leq 3## whence ##1 \in A##. • We claim that ##\sqrt{3}## is an...- JVEK7713
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- Abstract algebra Proof Supremum
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- Forum: Linear and Abstract Algebra