Recent content by k.ingleman

I think you'd use a sphere

I know that qenclosed = ρ*V and so i took qenclosed(9 *10^-6) divided by volume (4/3)*pi*(b^3 - a^3) and got p = .0141...I'm just not sure what to do next..Gauss' Law is integral(E.da) = Qenclosed/8.85×10−12

Homework Statement An insulator in the shape of a spherical shell is shown in cross-section at this site: http://kingleman.webs.com/apps/photos/photo?photoid=98095962 . The insulator is defined by an inner radius a = 4 cm and an outer radius b = 6 cm and carries a total charge of Q = + 9 μC...