Recent content by kaalaniz

ok thankyou. I appreciate your help.

wait one more problem. How do i get the correct direction of the displacement? I did inverse tangent of -201.79/-129.9 and i got 57.23 degrees. This isn't what the book says.

yes! I changed the d values and got the right answer. thankyou

sorry, i meant to type F_x = 25 I looked at the graph again. Should D_x be negative and I keep D_y positive because it is going up?

A_x=100 A_y=0 B_x=0 B_y=-300

C_x=-150cos30=-129.9 C_y=-150sin30=-75 d_x=200cos60=100 d_y=200sin60=173.21 F_x=100-129.9+100+25 F_y=-300-75+173.21=-201.79 square root of 25 squared plus -201.79 squared=203.33 meters tan^-1(-201.79/25)=-82.94 degrees

ok i have another question. I tried to use 30 degrees for the angle measurement for vector c and 60 degrees for vector D but I know that is not right. what are the angle measurements used for them?

ok that makes sense. thankyou.

[b]1. A person going for a walk follows a path. The total trip consists of four straight-line paths. At the end of the walk what is the person's resultant displacement measured from the starting point? The books says the answer is 240 m at 237 degrees. [b] Vector A is 100m East at 0°...