Recent content by kalpak

The sender is undergoing time dilation due to motion, so the second is "slower" in the sending system. Therefore, if the sender were to measure own emitted frequency, it would also be blue shifted (more waves fit in the slower second measurement window).

The comparison between photons and basketball (or any other projectile ) is wrong. A photon has the same measured velocity in both the sender and observer frames, not so with any other projectile.

Thanks for the prompt replies. If the photon is taking away energy from the sending system, then if the sender measures the frequency of the emitted light, it should also be frequency shift. How can one verify that?

Assume a object in motion emits a beam of light at an observer. The observer detects a frequency that is higher than the original frequency. That is the measured energy of the photon by this observer is higher than it was while emitting. How to account for this extra energy? thanks, kalpak