Recent content by kas8

im still not sure what voltage being zero has to do with this question? i came up with 2.65x10^7 m/s theory in physics is NOT my forte! :S appreciate the help, big time!

so i should figure out what the ke is if the Vstop is 2.00V...then u use that information to solve for vmax?

so what does the question mean when it asks "if the applied voltage is zero...?"

im trying to understand what the question is asking me for? the KE when the Vstop is 2.00? or when the voltage is zero?

ya i understand that part... so, if the applied voltage is zero, doesn't that make the kinetic energy zero? since KE=eV...? and if KE is zero... that makes the vmax zero too?

well i know that its used to increase the intensity of the negative plate to repel the electrons... the stopping voltage is the point at which the current stops because of that increased negative intensity... but i don't understand why there's a stopping voltage AND zero voltage applied... ??

In a photoelectric cell, the stopping voltage is 2.00V. If the voltage applied across this cell is zero, what is the maximum speed of the electrons from the photoelectric surface? Confused.