Recent content by Kaushy

I'm almost certain it is 4*T*sin80. Regardless, from my understanding, I'm not considering there to be a moment since the question in OP isn't actually a fixed point. I could not make that out from this diagram given. Thank you for both of your help.

When I am given this, seemingly similar problem (i have the solution), the formula for moment at point A is 0 = momentA - 20(5) - 20(5sin26.56) (counterclockwise positive). Why do we consider the moment as part of the equation in this and not the first one? (yes, assume the beam is weightless)

Homework Statement This is the diagram, and the question is written there too (sorry for blurry picture) Homework Equations My main question is that when you draw out the FBD, at point A, there is a force going up, and a force going to the right. Why isn't there a moment around A? I have had...