Recent content by kaylamalanie

im not sure which equation to use.

37.5 m? if the car starts at the origin, then its final position would be 62.5m and the truck starts at 50, its final position would be 100 m

would they be 12.5 m apart when the car reached 25m/s?

I finally got 62.5 m for the car! would it be 50.04 m for the truck?

using d=v0+.5at^2?

im referring to the t in the vf=vi+at. it was what i initially used.

2.78 s. I made the mistake because on my test my teacher said the t in the formula was squared which I didn't think it was, just confusing me more.

they would be 32.4 m apart?

It wasn't a typo, I used d=v0+.5at^2, is the equation wrong?

30.1 m for the truck. I knew distance equals velocity*time, but I have trouble relating things.

I got 52.5 m for the car. I don't understand how to find it for the truck.

calculating how far apart they are when the car has reached 25 m/s.

well it would take the car 1.67 s to accelerate from 20m/s to 25 m/s. this is where i get stuck. I tend to have trouble understanding what to do with the pieces of info I find. I understand the concept of trying to find the equation with the variable you're looking for to solve for, but I don't...

hang on, the initial velocity is 20 m/s i believe, it's the truck with the 18 m/s. so if i correct that, do I plug it in?

oh, that explains why my teacher wrote I was half through. do I then take that number and plug it into the same equation?