Recent content by kb1408
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Electric field at a distance from a charged disk
And thank you andrien for the link!- kb1408
- Post #11
- Forum: Introductory Physics Homework Help
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Electric field at a distance from a charged disk
There was an advertisement above that link earlier so I ignored it thinking it was tied to that ad. Alright, thanks for your help! cheers!- kb1408
- Post #10
- Forum: Introductory Physics Homework Help
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Electric field at a distance from a charged disk
Yes, that's what I did. Is it σ=Q/A then?- kb1408
- Post #8
- Forum: Introductory Physics Homework Help
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Electric field at a distance from a charged disk
E= (3.1E-6/(2*8.85E-12))(1-((.0001/(√(.00012)+(.0242)) so E= 1.79E5 N/C where: σ=3.1E-6 C/m2 ε0=8.85E-12 C2/N*m2 z=.01E-2 m r= 2.4E-2 m- kb1408
- Post #6
- Forum: Introductory Physics Homework Help
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Electric field at a distance from a charged disk
Doc Al, thanks for your quick reply. Unfortunately I am still doing something wrong. I am using 3.1E-6 C/m2 for σ. Is that wrong?- kb1408
- Post #4
- Forum: Introductory Physics Homework Help
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Electric field at a distance from a charged disk
A disk of radius 2.4 cm carries a uniform surface charge density of 3.1 μ C/m2. Using reasonable approximations, find the electric field on the axis at the following distances. I have used the equation E=(Q/ε0)(1/(4*pi*r2)) I also tried the equation E=(Q/2(ε0))(1-(z/(√(z2)+(r2))) Thanks...- kb1408
- Thread
- Charged Disk Electric Electric field Field
- Replies: 11
- Forum: Introductory Physics Homework Help