yes i got .075 for the period. but isn't that way too small considering the distance from center of the Earth to artifical satellite is bigger than the mean distance from the center of the Earth to the moon?
Kepler's Law help!
Use this equation: T^2 of A / R^3 of A = T^2 of B / R^3 of B
The moon has a period of 27.3 days and has a mean distance of 3.9*10^5 km from the center of the earth. Find the period of an artifical satellite that is 7.5*10^3 km from the center of the earth.
How do i...