Recent content by keishaap

Lol ever have one of those brain farts where you think things are harder than the seem? Yeah give me a break.

So what would it look like?

So would the fractions look like cos^2 x/sinx and sin^2x/cosx ?

So its 2(cosx/2sinx)-(sinx/cosx) do the 2 go on both fractions? And i thought you couldn't separate the fractions unless tgey had the same denominator?

Okay so i get 2(cos^2-sin^2)/(2sinxcosx) when i divide my sins what do i do with the 2 in the denominator?

Homework Statement Prove that cotx-tanx=2cot 2x Homework Equations Is 2cot 2x the same as 2(cos2x/sin2x) The Attempt at a Solution

Okay i thought they had to be the same because the teacher didn't show us any other way thanks!

But the formula also has pi/2 + x there's 2 A's and 2 B's

So cos( 0-x)?

How come the b is not a -x ?

Cos (pi/2) =0 Sin(pi/2)= 1

I have tried to use them but i totally get stuck like i don't know which is a or b and we are only given cos (a-b) = cosAcosB + sinAsinB

Homework Statement Which is equivalent to: cos(∏/2 + x) - cos(∏/2 - x)? A) -2cos(x) B) -2 C) 0 D)-2sin(x) Homework Equations Cos (A-B) The Attempt at a Solution I am totally stuck :( please help!