Recent content by ken.

Thanks. u re right. This really shows how indeterminate it can be.. But, what about the zero term do I also need to apply the L'Hospital there ? because without L'Hospital, the term evaluates to 0 and with L'Hospital, the term evaluates to -1 I think it is 0. Because the L'hospital applies to...

Hi I need INTegral from 0 to ∞ of : x*e^(-x) dx I use IBP: u = x, du = dx dv = e^(-x) dx, v = -e^(-x) uv - ∫v du = -x*e^(-x) - ∫ -e^(-x) dx I am trying to evaluate the uv term : -x*e^(-x) from 0 to ∞ for the ∞ term of -x*e^(-x) = -inf * 1/e^(inf) = -inf * 1/inf = 1 OR -inf *...