Recent content by kenano

Now it's all clear. Thank you very much.

Thank you for your answer Jacquelin. I still have some questions. -We have two constants in the solution to a first order equation because of the intermediate second order diff eq. But the original eq is a first order one. Then how could the second constant be determined in a boundary value...

\acute{y} = \frac{1}{t^{2}} -\frac{y}{t} - y^{2} To solve a Riccati type diff eq a particular solution is needed. In our case it is: y_{1} = -\frac{1}{t} By setting y= y_{1}+\frac{1}{u}= -\frac{1}{t}+\frac{1}{u} and differentiating this \acute{y}= \frac{1}{t^{2}}-\frac{u'}{u^{2}}...