Recent content by kevinfoss7

solved for t t=(-v0sinθ±( (v0sinθ)^2+2gz)^1/2)/g t=R(θ)/(v0cosθ)

sorry. Simpler way to state the given equations R(θ)=v0cosθt z=v0sinθt-1/2(gt^2)+z0

As a part of a lab, we were asked to find the theoretical relationship between R (the range of the projectile) and theta (the launch-angle). There is no recorded value for time. equations given are: R(θ)=x=d/dt v0x = v0xt-->R(θ)=v0xt v0x=v0cosθ z=...