Recent content by KevinO

Thank you it works out great now.I checked the book to make sure i did not type the units wrong but the book has it with the wrong units. She should have point that out though instead of making me frustrated thinking i doing something wrong. thanks again.

thank you for the welcome: Yes the units for it was suppose to be J/(K*kg) my solution was: P=ρVc∆θ/t=[1.2kg/(cm^3)×2500cm^3×1000J/(kg*K)×20K]/1s=6.0×10^7 J/(s) P*t= E = 6.0×10^7 J/s × 7200s = 4.32×10^11 J

the question states exactly: Air passes over an electric heater at a steady rate of 2500 cubic centimeters per second. the steady inlet flow temperature of the air is 20 degree celcius and the steady outlet temperature is 40 degree celcius. part a. what is the heat absorbed by the air...