When I do that, it shows that the tension is the net force for the system of boxes, and it shows that when the system is accelerating uniformly, the tension varies from greater than 1 to less than or equal to 2 times the value of static friction currently acting depending on the ratio of masses...
So, what you are saying is that static friction must actually be less than tension in that case, and that the amount less depends on the acceleration?
I think the reason this explanation gives me a problem is because if this is the case where tension is greater than static friction, it would...
That is the nature of how static friction at that interface would work. As tension was applied to the top box, the static friction would match the tension as long as tension was at or below the max static friction.
Hello,
I was wondering about a question and how it would be reconciled within Newton's laws of motion. Take a case where two boxes are stacked on top of each other, and the bottom box rests on a frictionless surface. Now, imagine a rope is attached to the top box, and tension is applied to...