Recent content by Kiziaru

Never mind, I figured it out. It only took me a day. :P Also, thanks for everything. You were a huge help.

It's here that I am getting lost. I have also have \frac{dY}{dX}=v+X\frac{dv}{dX} and set it equal to \frac{v-2}{v+4} but when I separate the variables I get \frac{(v+4)dv}{v^2+3v+2}=\frac{-dX}{X} Which does not integrate into something my textbook has.

Homework Statement Solve the following equation: (2x-y)dx+(4x+y-6)dy=0 Homework Equations Solve for M and N as a linear system of equations; and x_t = u + h y_t = v + k The Attempt at a Solution M = 2x-y=0 N = 4x+y-6=0 2x=y 4x+2x=6 6x=6 x=1 y=2 ∴ x_t=u+1 \\ dx=du...

Thanks! I've always lurked on this site, but I never posted because most of what I needed help with was already answered, until today. :frown: Also, I hate to sound dumb, but what wizardry is this? How can I make m and n into exponents? And is this part of a plan to get d(arctan(y/x))?

I'm rather bad at solving by inspection, and right now I am stuck on a problem I can't solve.1.http://www.texify.com/img/%5CLARGE%5C%21y%28x%5E2y%5E2-m%29dx%2Bx%28x%5E2y%5E2%2Bn%29dy%3D0.gif 2.The attempt at a solution...