Recent content by kkernodl
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Projectile Motion: Shooting over a hill
I was able to answer it using my original answer. I had to find the ratio of H/R, which is sinθ/4cosθ or (1/4)tanθ. I set (1/4)tanθ=H/R and solved for θ, which gave me θ=arctan(4H/R), which is the correct answer.- kkernodl
- Post #4
- Forum: Introductory Physics Homework Help
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K
Projectile Motion: Shooting over a hill
I found the position function in the x direction and set it equal to R/2. This gave me that the time, t, such that the position of x is R/2 is t=v0sin(2θ)/2gcosθ. I can use trig identities to simplify this to t=v0sinθ/g I can find the position function of y: Sy=v0t-4.9t2, but I'm not sure...- kkernodl
- Post #3
- Forum: Introductory Physics Homework Help
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K
Projectile Motion: Shooting over a hill
Homework Statement A projectile is fired with speed v0 at an angle θ from the horizontal as shown in the figure (see attachment). Homework Equations A. Find the highest point in the trajectory, H. Express the highest point in terms of the magnitude of the acceleration due to gravity g, the...- kkernodl
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- Hill Motion Projectile Projectile motion
- Replies: 3
- Forum: Introductory Physics Homework Help