I was wondering if the acceleration was uniform in this question? Why?
Plus would i need to apply the total mass lift and the mans weight so, 400kg+70kg?
There is and upward force due to acceleration and downward force due to g.
So do i do F = ma
F = 70x0.625
F =...
?I think this may be it:
S=ut+1/2at2
S=5
U=0
t=4
so 5= 0x4+0.5xax42
a= 5/ 0x4+0.5x42
a=0.625m/s2and for the change in mass
F=ma
so F=75x9.8^-1
mass of man on weighing scale = 75 kg
Homework Statement
g= 9.8 Nkg-1
Q. A lift has a mass of 400 kg. A man of mass 70 kg stands on a weighing machine fixed to the floor of the lift. Four seconds after starting from rest the lift has reached its maximum speed and has risen 5 m.
a) What...