Recent content by kndietz

I have tried to start calculating the density but I am stumped on how to do this without mass, and in order to find volume you need density... I tried converting from cm^3 to m^3, .08 and .026, and then I tried to make this into the 55% and 45% they represent... 4.4 and 1.17, combined is 5.57...

Please I need help ASAP! This is the problem: Cowen cites the deposition rate of BIF in the Hamersley Basin of Australia as 30 million metric tonnes per year. He says the ore is 55% iron (volume); iron has a density of 8 g/cm^3. Assume the rest of the ore is made of silica, which has a density...