Recent content by Krakadoros

will advise you not to believe everything wikipedia says. It is better to open a book with bibliography. For example i will say this : Before a month or something i read in wikipedia that , only mammals have hairs. But this is incorrect. Next time a bee or a spider, sit on you, catch it , and...

How many are you ? give me an example What about move back or front ? I mean, if first measure, let's say, 33mV and then move front for 1 meter and have a new measurement that is 36mV (this is because i would approach the source (it will be in my back, let's say)) then is not this a gradient...

you talk about "μWatt per m^2" and "Volt per meter" and that there is not a relationship between them. But there is a relationship between them. On free space conditions (impedance of 377 ohm) it is 1 V/m = 2.653 e^-3 W/m^2 = 2.653e^-4 mW/cm^2 = 2.661 e^-3 A/m = 3.350e^-5 Gauss =...

Nasu, with your answers, you help me to clear up my mind. I, just do not understand two points. 1)<…As the intensity is proportional to the square of the field…>> Do you mean that the intensity expressed as Watts per m^2 is proportional to the square of the intensity expressed as volts per...

A.T. My question was if the decrease of volts (by distance), in an electric field "A" is bigger than the decrease of volts in an electric field "B" , were "A" is stronger than "B" (at the same distance difference for both fields). If somebody know it, just tell me. Who says that the...

Nasu, your example is quite good, and help me. It seems, that my question is not so simple, but it is complicate. It involves a) unit <watt per meter^2> b) unit <volt per meter> c) potentiale d)potential differences ) Electro Magnetic Field's safe limits for health . May be Greg is right...

thanks for reply. First, i want to know if there is something wrong in my example and if my thoughts are right, somebody who knows about electric fields, to give me an answer. I think, my example is very clear. But I really want an answer. It seems , to me , very strange, that nobody has...

Dave, thanks for your reply. I check the regulator the way you told me, and I found 0.3 Ohms. This means that metals are grounded and there is a possibility for me to receive a shock, small possibility, but there is. I notice that in the electric board of my house, there is a test button, and I...

We have two difference electric fields A and B. We are standing at point W1 in field A and the potential at a point M1 which is 0.5 meter left is 10 volts while the potential at point M2, which is 0.5 meter right, is 5volts. The potential difference between M1 and M2 is 5volts and the strength...

Ι was wrong. Jbriggs 444 was referred to an uniform electric field. As i told before, "meter" in "volt / meter" do not show the distance between the charge-source and the charge at which the source's force, is applied. If this was the case, then, with increase this "meter", then we would have a...

https://www.physicsforums.com/attachments/74552 Νew modulation. E=Newton/Coulomb= Newton/(Joule/Volt)= Newton/((Newton*meter)/volt)= Volt/meter. The "meter " in "Volt / meter" comes from Joule, which is the Work produced from f (where f equals to 1 Nweton, or to the force needed for 1 kg mass...

i want to make a small modulation in my previous thoughts. The "meter" in "Volts per meter" for the Strength of an electric field, comes from Joules (..A=Newton/Coulomb=AND/(Joule/Volt)=N/((N*meter)/V)...). 1 Joule is the work from applying 1 Newton for 1 meter. This , 1 meter, is the one that...

you mean 45 millivolts (not 4.5) but if i follow this logic, means that for 4 meters the potential difference across this segment would be 60 millivolts and for 5 meters, 75 millivolts and so on. This means that the potential difference would increase with distance, but this is not logic. Except...

I measure the Electromagnetic Field Radiation at a point for example x distance from a source, and i am reading for ex. 15 milli volts per meter. Are these 15 millivolts per meter, equals to 15 milli volts ? I mean, if i do the opposite procedure, and receive a reading of 15 milli volts, at a...