Recent content by krazy19812

\mu_{s}ma i believe it is where mu sub s is the static coefficient

Also here is some spitballing i have been doing \SigmaFy=F_{N}-F_{G}=0 => F_{N}=F_{G}= ma I got 9.8m/s^{2}? not sure if that's right

Hey guys, I am having a little brain fart here, any help? Easy stuff Im trying to find the static and kinetic friction of an object on a certain surface. We used a modified atwood's machine and got the following results: Static mass required: 360g Kinetic mass required: 250g The mass...