Recent content by ^Kris
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Calculating Force to Propel Boat Across Shallow Lake
That's weird b/c I got the correct answer according to online, so why did the cosine calculation provide the correct answer for me?- ^Kris
- Post #10
- Forum: Introductory Physics Homework Help
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Calculating Force to Propel Boat Across Shallow Lake
Wow, I am an idiot. Thank you all for the help. I had to find the acceleration of the opposing force and subtract that from the acceleration of the boat, and then add that to the initial speed given. Thanks again.- ^Kris
- Post #7
- Forum: Introductory Physics Homework Help
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Calculating Force to Propel Boat Across Shallow Lake
I missed the part with the .857m/s as the initial, but I tried that and put it into the answer block and it says its wrong. I used V = Vi + at to solve for the final speed, but the online answer is saying "Did you accidentally divide or take the inverse in your calculation?" which i don't think...- ^Kris
- Post #6
- Forum: Introductory Physics Homework Help
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Calculating Force to Propel Boat Across Shallow Lake
Ok so I used F=ma to find a. I found the horizontal F by doing 245cos(35) and got 200.6922, and then divided that by the mass of the boat which is 390kg and got .3928m/s^2. I know the acceleration, and the time, but I do not know the initial V, therefore how can I find the Final V?- ^Kris
- Post #3
- Forum: Introductory Physics Homework Help
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Calculating Force to Propel Boat Across Shallow Lake
Homework Statement The figure below shows a worker poling a boat-a very efficient mode of transportation-across a shallow lake. He pushes parallel to the length of the light pole, exerting on the bottom of the lake a force of 245 N. Assume the pole lies in the vertical plane containing the...- ^Kris
- Thread
- Boat Force Lake
- Replies: 9
- Forum: Introductory Physics Homework Help