Recent content by Kugan

Ok so here is the issue I'm having: For problems with inclined planes I have always broken the Fg force down into its components: Fgy= mgcos(theta) Fgx = mgsin(theta) Usually the Fnety= Fgy+ Fn(there is no motion in the Y direction for let's say a car going around a banked curve)...

Hmmm... I thought I might offer something here just in simple terms. If you have 2.4amp*hr and 1.5 amp*hr then initially say the first second there will be 2.4*3600 = 2.4*3600 Coulombs/s and 1.5*3600/s so per s there is more charge flowing through assuming V is constant then P =iV the 2.4A*h...

The first time I read the problem I did a different way than was suggested. If the initial force parallel to the ground causes an inc in the Kinetic energy by 38% then a force at an angle of 62 degrees, there is only 46.9% of the original force being applied horizontally. How I got 46.9%...