Recent content by kuheli

i tried that way.no result found

a,b,c in continued proportion means a/b=b/c i.e b^2=ac

Re: ratio do you think the numerator of the fraction is y(2x+1)(x-1) or y(2x+1)(x-3) ?

Re: ratio and proportion what ? i am not getting you ...:confused:

hi , this is one simple math but i am not getting the answer. the work done by (x-3) men in (2x+1) days and the work done by (2x+1)men in (x+4) days are in the ratio of 3:10.find the value of 'x'.

hi , i am stuck with a problem . the problem is if a , b , c are in continued proportion ,then prove that (a+b+c)^2/(a^2 +b^2 +c^2) =(a+b+c)/(a-b+c) i have tried solving the problem in different way like breaking the formula of (a+b+c)^2 =a^2 +b^2 +c^2 + 2ab +2bc+2ca , then used...

thanks a lot ...

Re: mean proportion problem if a,b,c are in continued proportion prove that (a+b+c)^2/(a^2 +b^2 + c^2)=(a+b+c)/(a-b+c) i break the part -> (a+b+c)^2 into (a^2 +b^2+c^2+2ab+2bc+2ac) and then use componendo dividendo to the numerator and denominator to the problem,,, but its still not...

hi ... thanks a lot . there is another problem with which i am stuck .i tried but its getting more complicated and long without any positive sign.the numerical is: if a,b,c,d are in continued proportion prove that a/d=(a^3 +b^3 +c^3)/(b^3 + c^3 +d^3)

i am unable to figure out in which direction and how to proceed with this

if b is the mean proportion between a and c ,show that abc(a+b+c)^3 = (ab+bc+ca)^3

ya i got it .. thanks a lot :)

if b is the mean proportion between a and c ; prove that (a^2 - b^2 + c^2) / (a^-2 - b^-2 + c^-2) = b^4

using properties of proportion solve ( x^3 + 3x )/341 = (3x^2 + 1)/91