Recent content by KYUI

This is what it said: "x = +0.414cm or -2.41cm at the above two points the magnitudes of the two forces are equal. At point .414cm the magnitudes of both the forces are equal but the directions are same. But we require the forces to be in opposite direction. So the required position of the...

Thanks for answering my question. I really appreciate it. And I'm sorry I still don't understand :( I understand that r can be negative and relation to the origin but I don't understand how to determine which number (that I found for r) is used as the answer. If r is positive, the proton will...

Homework Statement A +2.0-nC charge is at the origin and a -4.0-nC charge is at x = 1.0-cm. At what x-coordinate could you place a proton so that is would experience no net force? [NOTE by me] I put q1 as the positive charge (+2.0nC) and q2 as the negative charge (-4.0nC). q0, of course...

oh i feel stupid. thank you very much haha i calculated it couple times before i posted it but I guess I had a mistake in it. Man, it took me awhile to write this too. anyways, thanks. :)

[FONT="Century Gothic"]Homework Statement A uniform electric field exists in the region between two oppositely charged parallel plates (1.64*10-2)m apart. A proton is released from rest at the surface of the positively charged plate and strikes the surface of the opposite plate in a time...