Recent content by laekoth

The drawing is correct, it's -90j. If i could scan the picture, i would. I guess I'm not crazy thinking the beam can't be in equilibrium, it's good to have a second opinion on that. Edit: professor confirmed the problem was intentionally unsolvable.

I had renamed the points to explain the question on here, and copied over my work incorrectly. To clarify I attempted to draw the problem: From how I understand the problem these should be correct: Moment at A: -F1(.2) + Rcy(.4) + -F2y(.6) = -90(.2) + Rcy(.4) + -sin45(180)(.6) = 0 I could...

Homework Statement a horizontal beam has a pin at 0m(point A), a 90N (-90i) force at .2m(point B), a pin at .4m(point C) and a 180N (-127.3i + -127.3j)at (45 degrees) force at .6m(point D). the pin at point A is attached to a vertical wall with rollers, the pin at point C can't move. The beam...