Recent content by Leah200

Okay. Should I find friction before I find tension? The question asked me to find tension and then solve for the coefficient of kinetic friction.

Let's say that the angle is 30 degrees, mass is 3.2kg, acceleration is 5.4m/s^2 for the second mass. So it's (3.2kg)(5.4m/s^2) = - (3.2kg)(9.8m/s^2)sin30 + FT - Ff, then 17.28kg/s^2 = -15.68kgm/s^2 + FT - Ff, then can I add them like this 32.96kgm/s^2 = FT - Ff? After that, can I then solve...

So for the second mass, it should be ma = -mgsinθ + FT - Ff, solve for FT, then should I solve for Ff?

So, for the block on the incline, should I use ma = -mgsinθ + FT to solve for FT. So basically, for the mass hanging use ma = mg - FT, and for the block on the inclined plane, use ma = -mgsinθ + FT? Should I add the two tensions together? If I look for the coefficient of kinetic friction, should...

Ok, I'll do that. I should have put mgsinθ, I think!

Oops, I should have written that the hanging mass would be ma = mg - FT, and the acceleration mass would be ma = mg + FT - Ff. I think the force for the hanging mass is negative and the force for the accelerating mass is positive.

According to my course, when I look for acceleration and tension, I have to use the equations ma = mg + FT for the first mass (the one hanging), then for the second mass (the one on the plane), I have to use FN = mgcos, Ff = miuFN and finally ma = mg - FT - Ff. Instead of finding acceleration, I...

The question asks for friction, unfortunately. It states I need to find tension and then friction.

It went something like this: Two blocks are connected by a pulley, one block (block 2, mass is 3.8kg) is on an inclined plane of 40 degrees while another block (block 1, mass is 1.8kg) is hanging by the pulley. Block 2 is accelerating up the plane at 1.2m/s^2. Find the tension and friction.

So, in order to find tension and friction, I just need to use ma = mg + FT for the first mass (the one hanging), then find the second tension by first finding normal force through using FN = mgcosθ, then find the coefficient of friction using μ = tan θ, then use Ff = μFN, and finally use ma = Fg...

The equation (μ = tan θ) comes from Fnet = mgsinθ - μmgcosθ. Supposedly, I can use it to calculate the coefficient of kinetic friction. I'll try that out. Thanks! How would solve it if I had to find the net tension of the two masses? I think the first one would just be Fnet = Fg -/+FT, and...

Homework Statement How do you find tension and friction on an inclined plane given acceleration, two masses and an angle? It's a pulley system, I suppose. Here's a diagram I drew: http://postimg.org/image/m9v9i2qy5/ Homework Equations Fg = ma The Attempt at a Solution I was thinking that I...