Recent content by Lemoine

Let △ABC be a triangle. Let AD and CE be its internal bisectors, with D lying on BC and E lying on AB. Given that ∠CED=18° and ∠ADE=24°, how can I find angles ∠A and ∠C without aid of softwares? Angle ∠B is easy to calculate, as ∠CED+∠ADE=∠CAD+∠ACE=∠A+∠C2=180°−∠B2 42°=180°−∠B2 ∠B=96° The other...