i used the thin lens equations twice.
1.) 1/f-1/di=1/do
1/11-1/27=1/di
di=18.6cm
2.) 1/f-1/do=1/di
1/19-1/18.6=1/di
di= -883.5cm
My calculations for my second image doesn't seem correct. My image should be to the left of my lens and not to the righ tof my lens.
1. An object is placed in front of a converging lens in such a position that the lens (f = 11.0 cm) creates a real image located 27.0 cm from the lens. Then, with the object remaining in place, the lens is replaced with another converging lens (f = 19.0 cm). A new, real image is formed. What is...