I see, the magnitudes of charges cannot be added through summation.
The charge on both capacitors will be equal, that is, half of the original of the charge carried by C. and thus the energy stored in each capacitor will be (½)2=¼ times the original C. Hence, the total energy will be 2×¼=½...
Thanks for your reply! It helped a lot in both my thinking, not just only on this question.
For (2), the initial charges go into the capacitors C1 and C2, by charge sharing. The charge at C1 is equal to that at C2. For the initial charge on C transferred to C2, the same amount will be...
This question was taken from the public examination in my country/region.
The answer from the marking scheme is, only statement 1 is correct and the others are wrong. Can anyone explain why the other statements are wrong?
1. Homework Statement
The following components are connected in series...