A friend pointed me in the direction of Schott Solar as a maker of high efficiency panels (see link below).
http://www.schottsolar.com/us/products/photovoltaics/schott-power-poly-275-285/
Has anyone ever looked at these panels? How do they stack up against others from performance and cost...
Hi there. I did thru same calculations with my electric bills.
I compare my numbers for october or last year where i have
79920 kWH and 36400 kVARH
S=√79920^2+36400^2
S=87818
ph=79920/87818=0.91, which is not bad, right?
Then we replaced Cooling Tower and my numbers droped to
62960 kWH...
I will defiantly not going to invest my money in this project! :)
But if seriously-I will go thru all what we learn, squeeze all juice out of it and send one big and smart e-mail to my boss. thanks god I'm not making desigions here, I'm only a "junior".
I like to learn new things too. And...
It's 60. so i go 60*5.6=336 kVA
But, that fire is already connected to that generator, and should be include in this 235 existing Amp! or...they never start fire pump, while doing investigative report and come up with 235 existing amps...
Oh, my favorite stuff!
The dipper we go-the more questions I have :)
But thanks a lot every one, I can only imagine how much in $/hr I have to pay to our electric engeener to explain me all that! Viva la internet ;)
p.s. pic of my fire pump name plate http://i42.tinypic.com/zkoeoy.jpg...
Thank you a lot everybody!
Of course I will hire a professional to prepare all paper work for annual fire inspection. The main purpose of my question-is self-understanding of process. I would like to know and understand, what I’m dealing with. So, is there any formula, I can use for estimate...
You got me! the water pump-is what bring that question in my mind. I have a fire pump as a part of this installation. I have about 235 amp been used, my question is can I add a load of 200 amp more to this generator? how much of "reserve" this water pump will need?
another limiting factor is...
But then, if I do my reverse engeenering,
979 Amp * 480 V ≈ 470 kW.
Not 650 kW.. Did I miss some adjustments for 3 Phase?
If i do 470 kW * 1.73 =813 kVA, but where is 650 kW?
Hi there!
I have here a CAT Standby 650 ekW 813 kVA 60 Hz 1800 rpm 480 Volts generator with CAT 3412C TA Diesel Engine.
Im trying to come up with maximum apm load which can be connected to this generator.
What formula should I use for that?
simple one W=V*A, where A=W/V good enought? Or...
So, any advice what questions should I ask my project engineers and installers? What brand/make of inverters i should take a closer look?
Because if we talking about 10% loss on inverter-its $2500 a month, so i want to maximize $ I'm getting back out of this system.
So, you saying that i should look for a boost inverter for my system?
A deal here that I'm looking for at this project more like an accountant, not an engineer. I mostly interested in "how much money i can get out of this system every month"
But yea, that 81% inverter efficiency drive me...
And i did. Here is his reply in case someone need it for the future:
The formula for average daily kwh is as follows:
Average Daily KWH = (System Size in STC) x (Sun-Hours) x (Inverter/Soil/System Derate) x (Tilt/Azimuth Derate)
For Sun-Hours at Hawaii, we would use 5.81.
For...
Hi there
I have an Photo Voltaic system size 141 kW DC. It gives me an about 13 000 kW/hr a month.(I'm in Hawaii)
We planning to install a new system, size ≈800 kW DC.
How can i calculate how much of kW/hr AC i will get out of new system?
Is there is any special formula to covert DC to AC...