Recent content by LindaNguyen

Here's what I've come up with: r x p = I'm getting 27. if I do Ii Wi = If Wf --->using I=mr^2 ; w=v/r ; r=CM=2.7m I end up with 27 also. now If Wf = 2(2.7)^2 + 6(0.7)^2 + 4(2.3)^2 * w I know I solve for W after this but I'm not sure if I have the numbers in the ( ) correct.

Ah, I get it now (kind of) L=IW (true for any object spinning around it's cm) L=RxP (around an exterior point) ----------------------------------------------------------- so, after I find the angular momentum about the small mass, I can set it to the whole system using L=IW, correct? also.. if...

I'm still a tad bit lost on part B. Should I be finding the angular momentum about its center of mass?

Thank you, Cepheid! I'm not very good at posting on forums so bare with me. I'll learn how to quote and etc. soon enough! Part A) Sorry for the typo, hehe. I have a million things going on right now. As for the rounding error, I'm still getting 2.666666. I'm trying to find the center of mass...

Homework Statement Suppose three masses are arranged as shown, connected by a rodless mass. (2 kg)-------(6 kg)--------(4 kg) 2m 3m a) If this object is free to rotate in space, about what point will it spin? Cm = 2(0) + 6(2) + 4(5)...